(4x^2-9)(x^2-2x+1)=0

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Solution for (4x^2-9)(x^2-2x+1)=0 equation:


Simplifying
(4x2 + -9)(x2 + -2x + 1) = 0

Reorder the terms:
(-9 + 4x2)(x2 + -2x + 1) = 0

Reorder the terms:
(-9 + 4x2)(1 + -2x + x2) = 0

Multiply (-9 + 4x2) * (1 + -2x + x2)
(-9(1 + -2x + x2) + 4x2 * (1 + -2x + x2)) = 0
((1 * -9 + -2x * -9 + x2 * -9) + 4x2 * (1 + -2x + x2)) = 0
((-9 + 18x + -9x2) + 4x2 * (1 + -2x + x2)) = 0
(-9 + 18x + -9x2 + (1 * 4x2 + -2x * 4x2 + x2 * 4x2)) = 0
(-9 + 18x + -9x2 + (4x2 + -8x3 + 4x4)) = 0

Combine like terms: -9x2 + 4x2 = -5x2
(-9 + 18x + -5x2 + -8x3 + 4x4) = 0

Solving
-9 + 18x + -5x2 + -8x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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